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Originally Posted by Scottnot
If that's what you want to believe, ok.
Still waiting to hear/read this from some reliable source.
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Think whatever you want.
Quote:
Originally Posted by Scottnot
0IRE corresponds to 0 voltage, or 0mV if you wish.
Actually, in digital, it's 0,0,0,0,0,0,0,0. No voltages, just ones and zeros.
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No it's not 0IRE that is know as baseline and black is at 7.5IRE in NTSC and that is equal to 53mV above baseline in NTSC. The video signal is 1 volt peak to peak and in NTSC active video gets 714mV and sync gets 286mV. That's not very easy to read on a scope so IRE units were invented and each IRE is equal to 7.14mV. So video is 100IRE and sync is 40IRE. So 7.14 * 7.5 = 53.55mV. Now in digital it's different 0mV equals 64bits in a 10-bit system like almost everything I use at work. So in binary it would be 00 0100 0000.
Quote:
Originally Posted by Scottnot
Correct . . . pretty much. Since your instructions seems to assume a pulge using two stripes, I would suggest adjusting brightness until the darker of the stripes matches "screen black" (becomes invisible) and the other stripe remains barely visible. On most plasmas and LCDs, this will result in a black luminance in the range of 0.4 to 0.8 cd/m^2 which is pretty darn black even in the dimmest of rooms - certainly isn't going to be "milky" by any stretch of the imagination.
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It has been a long time since I've looked at the levels of pluge but if I'm not mistaken they are 3.5IRE, 7.5IRE, and 10IRE and you would be looking for the 3.5IRE stripe.